# Line slope calculator 10x-y=40

**Straight line given by points A[4; 0] and B[5; 10]**

## Calculation:

**Slope-intercept form of line:**y = 10x-40

**Canonical form of the line equation:**10x-y-40 = 0

**Parametric form of the line equation:**

x = t+4

y = 10t ; t ∈ R

**Slope:**m = 10

**Slope angle of line: φ =**84°17'22″ = 1.4711 rad

**X intercept:**x

_{0}= 4

**Y intercept:**y

_{0}= q = -40

**Distance line from the origin:**d

_{0}= 3.9801

**The length of the segment AB: |AB| =**10.0499

**Vector: AB =**(1; 10)

**Normal vector: n =**(10; -1)

**Midpoint of the segment AB: M =**[4.5; 5]

**Perpendicular Bisector equation:**x+10y-54.5 = 0

**Vector OA = (4; 0) ; |OA| = 4**

**Vector OB = (5; 10) ; |OB| = 11.1803**

**Scalar product OA .OB = 20**

**Angle ∠ AOB = 63°26'6″ = 1.1071 rad**