The OS have a cairn not a currick marked at the top of Kip law .From the site of the stone (which is not 100 % accurate as I ‘m not sure which one it is as seen on GE but this will have little impact on the result as both extremes of the “wall “ occupy less than degree at the distance to Kip law plus I believe it is fairly central ) to the summit is 105 degrees which provides a declination of minus 3.9 . The required azimuth to get the minor standstill decliantion of minus 19.7 from the stone would have to be 131 degrees , quite a bit off .
|